Find the degree,roots,no.of real rootscomplete the table belowPOLYNOMIAL EQUATION→(3x+5)(2x-3)=0→(x²-9)(x-3)⁸(x³-1)=0→x(x²+1)(x+2)⁶=0→x⁴(x-3)²(x-7)⁷=0DEGREE→→→→ROOTS→→→→NO. OF REAL ROOTS→→→→​

Find the degree,roots,no.of real roots
complete the table below

POLYNOMIAL EQUATION
→(3x+5)(2x-3)=0
→(x²-9)(x-3)⁸(x³-1)=0
→x(x²+1)(x+2)⁶=0
→x⁴(x-3)²(x-7)⁷=0

DEGREE
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ROOTS
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NO. OF REAL ROOTS
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Answer:

degree
x=-\frac{5}{3},\:x=\frac{3}{2}
x=3,\:x=-3,\:x=1,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}
x(x²+1)(x+2)⁶=0

Step-by-step explanation: